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// Scilab Code Ex13.7: Ratio of electronic polarizability to ionic polarizability: Page-289 (2010)
epsilon_r = 4.9; // Absolute relative dielectric constant of material, farad per metre
n = 1.6; // Refractive index of dielectric material
// As (n^2 - 1)/(n^2 + 2)*(alpha_e + alpha_i)/alpha_e = N*(alpha_e + alpha_i)/(3*epsilon_0) = (epsilon_r - 1)/(epsilon_r + 2), solving for alpha_i/alpha_e
alpha_ratio = ((epsilon_r - 1)/(epsilon_r + 2)*(n^2 + 2)/(n^2 - 1) - 1)^(-1); // Ratio of electronic polarizability to ionic polarizability
printf("\nThe ratio of electronic polarizability to ionic polarizability = %4.2f", alpha_ratio);
// Result
// The ratio of electronic polarizability to ionic polarizability = 1.53
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