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//Chapter 20, Problem 8
clc;
Rp=12; //resistance
Vl=415; //3 phase supply
Vp=Vl/sqrt(3); //phase voltage
Ip=Vp/Rp; //phase current
Il=Ip;
pf=1; //power factor
P=sqrt(3)*Vl*Il*pf; //power dissipated
printf("Total power dissipated = %.2f kW",P/1000);
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