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//Basic Circuit Concepts
//page no-1.19
//example1.14
disp("Applying KVL to the mesh");
disp("15 - 50*I - 50*I - 5*I");
I=15/105;
printf("I=15/105 = %.2f Amp", I);
V=15-(50*0.143);
printf("\nVoltage at node 2 = 15 - 50*I = %.2f Volt", V);
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