1511/CH2/EX2.36/ex2_36.sce


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// Example 2.36 page no-125
clear
clc

Ct=20 //pF
v1=5 //v
v2=6 //v
Ct2=Ct*sqrt(v1/v2)
printf("Therefore, decrease in the value of capacitance is\nCt1-Ct2=%.2f pF",Ct-Ct2)