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clear
clc
disp('the first row of A denotes the scores of A and that of B denotes that of B')
A(1,:)=[12 115 6 73 7 19 119 36 84 29];
B(1,:)=[47 12 16 42 4 51 37 48 13 0];
disp('the second row of A annd B denotes the corresponding deviation ')
for i=1:10
A(2,i)= A(1,i)-51;
B(2,i)=B(1,i)-51;
end
disp('the third row of A and B denotes the corresponding deviation square')
for i=1:10
A(3,i)= A(2,i)^2;
B(3,i)=B(2,i)^2;
end
A
B
b=0;
disp('sum of second row elements of A=b=')
for i=1:10
b=b+A(2,i);
end
disp(b)
c=0;
disp('sum of second row elements of B=c=')
for i=1:10
c=c+B(2,i);
end
disp(c)
d=0;
disp('sum of third row elements of A=d=')
for i=1:10
d=d+A(3,i);
end
disp(d)
e=0;
disp('sum of second row elements of B=e=')
for i=1:10
e=e+B(3,i);
end
disp(e)
disp('arithmetic mean of A=')
f=51+b/10
disp('standard deviation of A=')
g=(d/10-(b/10)^2)^0.5
disp('arithmetic mean of B=')
h=51+c/10
disp('standard deviation of A=')
i=(e/10-(c/10)^2)^0.5
disp('coefficient of variation of A=')
(g/f)*100
disp('coefficient of variation of B=')
(i/h)*100
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