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//CHAPTER 8- DIRECT CURRENT MACHINES
//Example 9
disp("CHAPTER 8");
disp("EXAMPLE 9");
//4 Pole 230 V lap wound shunt motor with 600 conductors. RPM 1800
//VARIABLE INITIALIZATION
P=4; //number of poles
v_t=230; //in Volts
I_l=52; //in Amperes
Z=600; //tottal number of conductors
r_f=115; //in Ohms
d=30/100; //airgap diameter from cm to m
l=20/100; //effective length of pole
B=4100/10000; //flux density from Gauss to Wb/m^2
//SOLUTION
I_f=v_t/r_f; //I_f is same as I_sh
I_a=I_l-I_f; // armature current
ar=(%pi*d*l)/P; //area of pole
phi=ar*B; //phi = flux
A=P; //for lap winding
T=(phi*Z*I_a)/(2*%pi*A); //Torque developed
disp(sprintf("The torque developed in the motor is %.4f N-m",T));
//The answer is different as 'A' has not been included in the denominator(in the book)
//END
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