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//CHAPTER 8- DIRECT CURRENT MACHINES
//Example 23
disp("CHAPTER 8");
disp("EXAMPLE 23");
//VARIABLE INITIALIZATION
v=230; //in Volts
r_a=0.4; //in Ohms
r_f1=115; //in Ohms
I_a=20; //in Amperes
N1=800; //in rpm
N2=1000; //in rpm
//SOLUTION
I_f1=v/r_f1; //redundant step
E_b1=v-(I_a*r_a);
//rearranging the equation, we get,
r_f2=((E_b1*N2)/((v*N1)-(N1*I_a*r_a)))*r_f1;
r_f2_dash=r_f2-r_f1;
disp(sprintf("The external resistance is %f Ω",r_f2_dash));
//The answer is slightly different due to the precision of floating point numbers
//END
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