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//CHAPTER 8- DIRECT CURRENT MACHINES
//Example 2
disp("CHAPTER 8");
disp("EXAMPLE 2");
// 230 V DC shunt machine
//VARIABLE INITIALZATION
v_t=230; //terminal voltage in Volts
r_a=0.5; //armature resistance in Ohms
r_f=115; //shunt field resistance in Ohms
I_l=40; //line current in Amperes
//SOLUTION
//for generator
I_f=v_t/r_f; //current through the shunt field winding
I_a=I_l+I_f; //Armature Current
E_a=v_t+(I_a*r_a); //E_a=emf of generator
//for motor
I_f=v_t/r_f;
I_a=I_l-I_f;
E_b=v_t-(I_a*r_a); //E_b=emf of motor
//ratio of speed as generator to speed as motor
ratio=E_a/E_b; //E_a:E_b=(k_a*flux*N_g):(k_a*flux*N_m) =>E_a:E_b=N_g:N_m (as flux is constant)
disp(sprintf("The ratio of speed as a generator to the speed as a motor is %.3f",ratio));
//END
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