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//CHAPTER 7- SINGLE PHASE TRANSFORMER
//Example 17
disp("CHAPTER 7");
disp("EXAMPLE 17");
//VARIABLE INITIALIZATION
va=200000; //
ironLoss=1000; // Watts
cuLoss=2000; //Watts
pf=0.8;
//
//SOLUTION
//
Pout=va*pf;
loss=ironLoss+cuLoss;
Pin=Pout+loss;
eff=Pout*100/Pin;
disp("SOLUTION (a)");
disp(sprintf("The percent efficiency at full load is %f",eff));
//
//at half load
Pout=va*pf/2;
loss=ironLoss+cuLoss*(1/2)^2;
Pin=Pout+loss;
eff=Pout*100/Pin;
disp("SOLUTION (b)");
disp(sprintf("The percent efficiency at full load is %f",eff));
//
//fraction x of copperloss=ironloss for maximum efficiency
//x^2.cuLoss=ironLoss
x=sqrt(ironLoss/cuLoss);
Pout=x*va*pf;
loss=ironLoss+cuLoss*x^2;
Pin=Pout+loss;
eff=Pout*100/Pin;
disp("SOLUTION (c)");
disp(sprintf("The percent efficiency at %f load is %f ",x,eff));
disp(" ");
//
//END
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