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//CHAPTER 3- THREE-PHASE A.C. CIRCUITS
//Example 1
disp("CHAPTER 3");
disp("EXAMPLE 1");
//VARIABLE INITIALIZATION
v_l=400; //line voltage in Volts
r=15; //resistance in Ohms
xc=10; //capacitive resistance in Ohms
//SOLUTION
//solution (i)
v_ph=v_l/sqrt(3);
disp(sprintf("(i) The phase voltage is %f V",v_ph));
//solution (ii)
z_ph=sqrt((r^2)+(xc^2));
I_l=v_ph/z_ph;
disp(sprintf("(ii) The line current is %f A",I_l));
//solution (iii)
//phase current = line current since connection is star
disp(sprintf("(iii) The phase current is %f A",I_l));
//solution (iv)
pow_fact=r/z_ph;
disp(sprintf("(iv) The power factor of the circuit is %f (leading)",pow_fact));
//solution (v)
p=sqrt(3)*v_l*I_l*pow_fact;
disp(sprintf("(v) The total power absorbed is %f W",p));
//solution (vi)
va=sqrt(3)*v_l*I_l;
disp(sprintf("(vi) The apparent power is %f VA",va));
var=sqrt((va^2)-(p^2));
disp(sprintf("The reactive power is %f VAR",var));
//Answers (v) and (vi) are different due to precision of floating point numbers
//END
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