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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
//Example 22 (mentioned as 'example 21' in the book)
clc;
disp("CHAPTER 2");
disp("EXAMPLE 22");
//VARIABLE INITIALIZATION
L=0.1 //in Henry
C=8*10^-6 //in Farad
R=10 //in Ohms
//SOLUTION
//solution (i)
fr=1/(2*%pi*sqrt(L*C)); //resonant frequency
disp("SOLUTION (i)");
disp(sprintf("For series circuit, resonant frquency is %3f Hz", fr));
disp(" ");
//solution (ii)
w=2*%pi*fr;
Q=w*L/R;
disp("SOLUTION (ii)");
disp(sprintf("The Q-factor at resonance is %3f kΩ", Q));
//solution (iii)
bw=R/(2*%pi*L);
f1=fr+bw/2;
disp("SOLUTION (iii)");
disp(sprintf("Half power frequencies are %3f Hz and %3f Hz", f1,fr));
//END
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