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//CHAPTER 2- STEADY-STATE ANALYSIS OF SINGLE-PHASE A.C. CIRCUIT
//Example 22 // read it as example 21 in the book on page 2.75
disp("CHAPTER 2");
disp("EXAMPLE 22");
//VARIABLE INITIALIZATION
L=0.1 //in Henry
C=8 //in mf, multiply by 10^-6 to convert to f
R=10 //in ohms
//SOLUTION
//solution (i)
//Resonance frequency for a series RLC circuitf = 1/2.π.sqrt(LC)
fr=1/(2*%pi*sqrt(L*C*10^-6));
disp("SOLUTION (i)");
disp(sprintf("For series circuit,Resonant frquency is %3.2f Hz", fr));
disp(" ");
//solution (ii)
//Q-factor is Q=w.L/R= 2.π,fr.L/R
w=2*%pi*fr;
Q=w*L/R;
disp("SOLUTION (ii)");
disp(sprintf("The Q-factor at resonance is %3.2f kΩ", Q));
//
//solution (iii)
//Bandwidth, BW, (f2-f1)=R/(2.π.L), where f1,f2 half power frequencies
//f1=fr-BW/2
//f2=fr+BW/2
bw=R/(2*%pi*L);
f1=fr-bw/2;
f2=fr+bw/2;
disp("SOLUTION (iii)");
disp(sprintf("half frequency 1 is %3.2f Hz", f1));
disp(sprintf("half frequency 2 is %3.2f Hz", f2));//
//
//END
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