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//CHAPTER 10- THREE-PHASE INDUCTION MACHINES
//Example 10
disp("CHAPTER 10");
disp("EXAMPLE 10");
//VARIABLE INITIALIZATION
P=6; //number of poles
f=60; //in Hertz
p=48; //stator input in Watts
N_r=1140; //in rpm
cu_loss=1.4; //stator copper loss in Watts
cr_loss=1.6; //stator core loss in Watts
me_loss=1; //rotor mechanical loss in Watts
//SOLUTION
N_s=(120*f)/P;
s=(N_s-N_r)/N_s;
p_g=p-(cu_loss+cr_loss); //rotor input
p_m=p_g*(1-s); //output mechanical power
p_sh=p_m-me_loss; //shaft power
eff=p_sh/p;
disp(sprintf("The motor efficiency is %f %%",eff*100));
//END
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