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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 6
disp("CHAPTER 1");
disp("EXAMPLE 6");
//VARIABLE INITIALIZATION
non=4; //number of nodes
nob=6; //number of branches
//SOLUTION
nome=nob-non+1; //number of mesh equations
disp(sprintf("Number of mesh equations are %d",nome));
none=non-1;
disp(sprintf("Number of node equations are %d",none));
//(5/2)I1+(-2)I2+(-1/2)I3=4.....eq (1)
//(0)I1+(0)I2+(1)I3=-2..........eq (2)
//(-2)I1+(10/3)I2+(-1/3)I3=0....eq (3)
//using matrix method to solve the set of equations
A=[5/2 -2 -1/2;-2 10/3 -1/3;0 0 1];
b=[4;0;-2];
x=inv(A)*b;
I=x(1,:); //to access the 1st element of 3X1 matrix
disp(sprintf("The current from the source V is %d A",I));
//END
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