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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 58
disp("CHAPTER 1");
disp("EXAMPLE 58");
//VARIABLE INITIALIZATION
v1=20; //LHS voltage source in Volts
v2=5; //RHS voltage source in Volts
r1=100; //LHS resistance in Ohms
r2=2; //in Ohms
r3=1; //in Ohms
r4=4; //in Ohms
r5=1; //RHS resistance in Ohms
//SOLUTION
//applying Thevenin's Theorem
//Thevnin's equivalent resistance, r_th is same as r_AB
r_th=((r3+r5)*r2)/((r3+r5)+r2);
v_th=(v1-v2)/2; //from the equation
I1=v_th/(r4+r_th);
v1=I1*r4;
disp(sprintf("By Thevenin Theorem, the value of V is %d V",v1));
//applying Norton's Theorem
//Norton's equivalent resistance, r_n is same as r_AB
r_n=((r3+r5)*r2)/((r3+r5)+r2);
I_n=(v1-v2)/r2; //since v_A=0
I2=r_n*(I_n/(r4+r_n));
v2=I2*r4;
disp(sprintf("By Norton Theorem, the value of V is %d V",v2));
//END
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