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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 54
disp("CHAPTER 1");
disp("EXAMPLE 54");
//VARIABLE INITIALIZATION
v=5; //voltage source in Volts
r1=1; //LHS resistance in Ohms
r2=5; //in Ohms
r3=1; //in Ohms
r4=1; //RHS resistance in Ohms
I=10; //current source in Amperes
//SOLUTION
//on deactivating the current source, current I1 flows in the circuit
req1=r1+r3+r4;
I1=v/req1;
vab1=v-(I1*r1); //(I1*r1) is voltage drop across 1Ω resistance
I2=I/req1;
vab2=vab1+(I2*r1); //(I2*r1) is voltage drop across 1Ω resistance
rth=r1+((r3*r4)/(r3+r4));
Ith=vab2/(rth+r2);
Rth=(6/5)+(3/4);
req2=10+2;
I3=9/12;
disp(sprintf("The value of the current is %f A",I3));
//END
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