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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 40
disp("CHAPTER 1");
disp("EXAMPLE 40");
//VARIABLE INITIALIZATION
v1=20; //in Volts
v2=10; //in Volts
r1=5; //top resistance in Ohms
r2=10; //bottom resistance in Ohms
r3=5; //in Ohms
r4=5; //in Ohms
r5=10; //in Ohms
//SOLUTION
//(5)I1+(10)I3+(-10)I4=20............eq (1)
//(0)I1+(10)I3+(10)I4=-50............eq (2)
//(5)I1+(20)I3+(0)I4=-30.............eq (3) (eq(1) + eq(2))
//Since the determinant of matrix A is 0, hence, the set of these equations cannot be solved by matrix method
//So, solving them directly,
I3=-15/25;
I1=-3-(3/5);
I4=-5-(-3/5);
I=I1+3+5;
disp("The currents (in Amperes) flowing in different branches are:");
disp(I1);
disp(I3);
disp(I4);
disp(sprintf("The total current is %f A",I));
//END
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