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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 28
disp("CHAPTER 1");
disp("EXAMPLE 28");
//VARIABLE INITIALIZATION
I1=5; //current source in Amperes
va=100; //voltage source in Volts
r1=20; //in Ohms
r2=10; //in Ohms
r3=20; //in Ohms
//SOLUTION
In=I1-(va/r1); //since a and b are shorted hence va=vb
rn=r1+((r3*0)/(r3+0));
I=(rn*In)/(rn+r2);
disp(sprintf("By Norton Theorem, the value of I is %d A",I));
//END
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