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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 22
clc;
disp("CHAPTER 1");
disp("EXAMPLE 22");
//VARIABLE INITIALIZATION
I1=20; //current source in Amperes
v1=10; //voltage source in Volts
v2=40; //voltage source in Volts
r1=8; //in Ohms
r2=5; //in Ohms
r3=4; //in Ohms
r4=12; //in Ohms
//SOLUTION
//by using mesh analysis the following equations are obtained
//(17)I2+(-4)I3=110.......eq (1)
//(-1)I2+(4)I3=10.........eq (2)
//solving the equations by matrix method
A=[17 -4;-1 4];
b=[110;10];
x=inv(A)*b;
I2=x(1,:); //to access the 1st element of 2X1 matrix
I3=x(2,:); //to access the 2nd element of 2X1 matrix
I=I3;
disp(sprintf("By mesh analysis, the value of I is %f A",I));
//END
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