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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 15
clc;
disp("CHAPTER 1");
disp("EXAMPLE 15");
//VARIABLE INITIALIZATION
v=7; //voltage source in Volts
I=7; //current source in Amperes
r3=1; //in Ohms
//SOLUTION
//(1)I1+(-4)I2+(4)I3=7............eq (1)
//(-1)I1+(6)I2+(-3)I3=0...........eq (2)
//(1)I1+(0)I2+(-1)I3=7............eq (3)
//solving the equations by matrix method
A=[1 -4 4;-1 6 -3;1 0 -1];
b=[7;0;7];
x=inv(A)*b;
I1=x(1,:); //to access the 1st element of 3X1 matrix
I2=x(2,:); //to access the 2nd element of 3X1 matrix
I3=x(3,:); //to access the 3rd element of 3X1 matrix
vx=-(I3*r3);
disp(sprintf("By Mesh analysis, the value of Vx is %d V",vx));
//END
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