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//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS
//Example 12
disp("CHAPTER 1");
disp("EXAMPLE 12");
//VARIABLE INITIALIZATION
v=10; //voltage source in Volts
I=5; //current source in Amperes
r1=2; //in Ohms
r2=2; //in Ohms
r3=4; //in Ohms
//SOLUTION
//deactivating current source
v1=(v/r1)/((1/r1)+(1/r2)+(1/r3));
I1=v1/r3;
//deactivating voltage source
v2=I/((1/r1)+(1/r2)+(1/r3));
I2=v2/r3;
I_tot=I1+I2; //since I1 and I2 are in same direction
disp(sprintf("By Superposition Theorem, the current through resistor R3 is %d A",I_tot));
//END
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