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-->exec('C:\Users\sangeet\Documents\Scilab\Circuits\Chapter 4\exa4.5.sce', -1)
((v_1-30)-v_2)/2-1+(v_1-v_2)/10+(v_1-50)/5=0 -------- Equation 1
(v_2-v_1)/10+(v_2-(v_1-30))/2+v_2-7=0 --------- Equation 2
Rearrangement then yields a pair of equations in standard form,
0.8v_1-0.6v_2=26
-0.6v_1+1.6v_2=-8
Voltage at Node 1(in Volts)=
40.
Voltage at Node 2(in Volts)=
10.
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