1385/CH9/EX9.16/9_16.sce


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clc
//initialisation of variables
c= 1 //M
Kb= 5.3*10^-5
pKw= 14
//CALCULATIONS
pH= pKw+0.5*log10(Kb)+0.5*log10(c)
//RESULTS
printf (' pH of solution = %.2f ',pH)