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//example2.8
clc
disp("P=4, A=P=4 as lap, V=230 V, Z=250")
disp("psi=30mWb=30*10^-3 Wb, I_a=40 A")
disp("From voltage equation, V=E_b+[(I_a)*(R_a)]")
disp("230=E_b+(40*0.6)")
e=230-(40*0.6)
disp(e,"Therefore, E_b(in V)=")
disp("E_b=(psi*P*N*Z)/(60*A)")
disp("Therefore, 206=(4*N*250*30*10^-3)/(60*4)")
n=(206*240)/(250*4*30*10^-3)
disp(n,"N(in rpm)=")
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