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//Example 5.8
//Newton Raphson Method
//Page no. 163
clc;clear;close;
deff('x=f(x)','x=x-exp(-x)')
deff('x=f1(x)','x=1+exp(-x)')
printf('n\txn\t\t\f(xn)\t\tf1(xn)\t\tXn+1\t\tError\n')
printf('-----------------------------------------------------------------------------------------------------\n')
x0=0.5;e=0.00001
for i=1:4
x1=x0-f(x0)/f1(x0)
e1=abs(x0-x1)
printf(' %i\t%.10f\t%.10f\t%.10f\t%.10f\t%.10f\n',i-1,x0,f(x0),f1(x0),x1,e1)
x0=x1;
if abs(x0)<e then
break;
end
end
printf('\n\nThe solution of this equation after %i Iterations is %.10f',i,x1)
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