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//Example 20.2
//Five Point Formula
//Page no. 683
clc;clear;close;
A=[-4,1,1,0;1,0,-4,1;1,-4,0,1;0,1,1,-4];
B=[-25;-150;-25;-150];
u1=inv(A)*B;
j=0;k=1
for i=1:4
j=j+1;
printf('\nu%i%i = %g\n',k,j,u1(i))
if i==2 then
j=0;k=2
end
end
printf('\n\n U = \n')
for i=1:4
printf('\n')
for j=1:4
if j==1 then
u(i,j)=0
elseif j==4
u(i,j)=100
elseif (i==1 | i==4) & j==2
u(i,j)=25
elseif i==1 | i==4
u(i,j)=u(i,j-1)*2
else
u(i,j)=u1((j-1)*2-i+2)
end
printf('\t%g\t',u(i,j))
end
end
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