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//Calculate efficiency on unity pf at different cases
clc;
clear;
Pi=25*(10^3);
E1=2000;
E2=200;
Pil=350;
Pc=400;
// Full load efficiency
nfl=Pi*100/(Pi+Pil+Pc);
//Half Load efficiency
Pihl=Pi/2;// Half Load
nhl=Pihl*100/(Pihl+Pil+(Pc/4));
// Load at which maximum efficiency occurs
Piml=sqrt(Pil/Pc)*Pi;
Pcm=Pc*((Piml/Pi)^2);
printf('a) Efficiency at full load = %f percent \n',nfl)
printf('b) Efficiency at half load = %f percent \n',nhl)
printf('c) Maximum Efficiency will occur at %f KVA and the losses are each %d watt. \n',(Piml/1000),Pcm)
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