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//To determine the range and current and deflection at various conditions
clc;
clear;
I=25;
theta=90;
// Various conditions
ta=360; // Angle in case a
tb=180; // Angle in case b
Ic=20; // Current in case c
// theta directly proportional to the square of the current
Ia=sqrt(ta*(I^2)/theta);
Ib=sqrt(tb*(I^2)/theta);
tc=((Ic/I)^2)*theta;
printf('a) Full Scsle deflection (360) current = %g A \n',Ia)
printf('b) Half Scsle deflection (180) current = %g A \n',Ib)
printf('c) Deflection for a current of 20 A = %g degrees \n',tc)
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