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//Current through AB using Nortons theorem
clc;
clear;
// Resitances in order from the 2V side
R1=2;
R2=12;
R3=1;
R4=3;
// Voltage Sources
V1=2;
V2=4;
//Using Superposition principle
Iab1=V2/R4;
I1=V1/(R1+(R2*R3/(R2+R3))); // Current drawn from 2V supply
Iab2=I1*R2/(R1+R2);
Iab=Iab1+Iab2; // Current source
Reff= R3 +((R1*R2)/(R1+R2));
Zth= Reff*R4/(Reff+R4);
Zl=2; // Resistor Connected between AB
Current=Iab*(Zth/(Zth+2)); // Current through branch AB
// Errorless Calculation, In the textbook approximations are done
printf('The Current through 2 ohm resistor in branch AB = %g A\n',Current)
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