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First,for the nominal resistance values given,
the bridge is set at anull with I=0,because
Va = 0.909091 V
With I=0 we get
Vb = 0.909091 V
When R3 increases by 1 ohm to 1001 ohm, Va becomesVa = 1.666667 V
which shows that the voltage at b must increase by 0.0008 V to renull the bridge.
This can be proved by current,from equation and Delta V=0,found from
I = 0.000016 A
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