1271/CH14/EX14.38/38.txt


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 # PROBLEM 38 # 
Standard formula used 
  lambda = h/(2*m*E)^1/2.

 de-Broglie wavelength of electron - (1) In first case is 0.548627 A. 
 (2) In second case is 1.734911 A. 
 (3) In third is 12.267676 A.