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clear;
clc;
// Stoichiometry
// Chapter 2
// Basic Chemical Calculations
// Example 2.1
// Page 17
printf("Example 2.1, Page 17 \n \n");
// solution
// NH4Cl
M = 14+4+35.5 // [g] (molar mass of NH4Cl)
n=5 // [mol]
m = M*n // [g]
printf("5 mol of NH4Cl = "+string(m)+" [g]")
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