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//Example 5.3
//Page 256
k=7//from equation 5.14 on page 256
disp('Using the value of k')
disp('Using the value of k, the number of crosspoint determined are')
2*7*16
disp('The number of bits of memory can be determined are')
N=[2*7*128*4]+[7*128*8]+[7*128*7]
//Result
//The composite implementation complecity is 430 equivalent crosspoints.
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