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//Example 5.1
//Page243
//Refer to table 5.2 on page236
disp('From the table, space expansion factor of 0.234 is 0.002. Hence the utilization of each interstage is given by')
0.1/0.234
p=1-[(1-0.427)^2]// probability that one of two links in series is busy
disp('Therefore, the expected number of paths to be tested are,')
Np=[1-(0.672)^15]/(1-0.672)
//Result
//Only 3 of the 15 paths should be tested before an idle path is found
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