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//Example 5.5
//Page 534
//Refer figure 12.5 on page 533
disp('From fig, it can be that the output circuit utilization for B=0.1 and N=24 is 0.8.')
N=24
op=0.8
disp('Thus the carried traffic intensity is ')
N*op
disp('Since the blocking probability is 0.1, the maximum level of offered traaffic is,')
A=[19.2/(1-0.1)]
disp("Result")
disp("A = 21.3 erlangs")
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