blob: 018da33d4f3893855bde3da154f63a312b8dfd13 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
|
// Electric Machinery and Transformers
// Irving L kosow
// Prentice Hall of India
// 2nd editiom
// Chapter 4: DC Dynamo Torque Relations-DC Motors
// Example 4-19
clear; clc; close; // Clear the work space and console.
// Given data
// From the calculations of Ex.4-16 , Ex.4-17 , Ex.4-18 we get no-load and
// full-load speeds as follows
S_n1 = 1810 ; // No-load speed in rpm (Ex.4-16)
S_f1 = 1603 ; // Full-load speed in rpm (Ex.4-16)
S_n2 = 1806 ; // No-load speed in rpm (Ex.4-17)
S_f2 = 1231 ; // Full-load speed in rpm (Ex.4-17)
S_n3 = 1311 ; // No-load speed in rpm (Ex.4-18)
S_f3 = 505 ; // Full-load speed in rpm (Ex.4-18)
// Calculations
SR_1 = ( S_n1 - S_f1 ) / S_f1 * 100 ; // Speed regulation for shunt motor
SR_2 = ( S_n2 - S_f2 ) / S_f2 * 100 ; // Speed regulation for compound motor
SR_3 = ( S_n3 - S_f3 ) / S_f3 * 100 ; // Speed regulation for series motor
// Display the results
disp("Example 4-19 Solution : ");
printf(" \n a: SR(shunt) = %.1f percent \n ", SR_1 );
printf(" \n b: SR(compound) = %.1f percent \n ", SR_2 );
printf(" \n c: SR(series) = %.1f percent \n ", SR_3 );
|
