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clc;
clear;
//Example 5.19
mw_dot=5; //Water flow rate in [kg/s]
Cpw=4.18; //Heat capacity of water [kJ/kg.K]
t1=303; //[K]
t2=343; //[K]
Q=mw_dot*Cpw*(t2-t1) //[kJ/s]
Q=Q*1000; //[W]
T1=413; //[K]
T2=373; //[K]
dT1=T1-t2 //[K]
dT2=T2-t1 //[K]
dTlm=dT1 ///[K]
hi=1000; //[W/sq m.K]
ho=2500; //[W/sq m.K]
Rd=1/(0.714*1000) //Fouling factor[m^2.K/KW]
U=1/(1/hi+1/ho+Rd) //[W/sq m.K]
A=Q/(U*dTlm) //[sq m]
printf("\nHeat transfer area is %f sq m",A);
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