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clc;
clear;
//Example 2.49
//Given
k=300 //W/(m.K)
h=20 //W.(sq m.K)
P=0.05 //[m]
A=2 //[sq cm]
A=A/10000 //[sq m]
T0=503 //[K]
T_inf=303 //[K]
theta_0=T0-T_inf //[K]
m=sqrt(h*P/(k*A))
//CASE 1: 6 Fins of 100 mm length
L1=0.1 //Length of fin in [m]
Q=sqrt(h*P*k*A)*theta_0*tanh(m*L1) //[W]
//For 6 fins
Q=Q*6 //for 6 fins [W]
//CASE 2: 10 fins of 60 mm length
L2=60 //[mm]
L2=L2/1000 //[m]
Q2=sqrt(h*P*k*A)*theta_0*tanh(m*L2); //[W]
Q2=Q2*10 //For 10 fins
printf("As,Q for 10 fins of 60 mm length( %f W) is more than Q for 6 fins of 100 mm length (%f W).\n The agreement-->10 fins of 60 mm length is more effective",Q2,Q);
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