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clc;
clear;
//Example 2.46
dia=3 //[mm]
dia=dia/1000 //[m]
r=dia/2 //radius in[m]
k=150 //W/(m.K)
h=300 //W/(sq m.K)
T0=413 //[K]
T_inf=288 //[K]
A=%pi*(r^2) //Area in [sq m]
P=%pi*dia //[W/sq m.K]
Q=(T0-T_inf)*sqrt(h*P*k*A) //Heat dissipated in [W]
printf("Heat dissipated by the rod is %f W",Q)
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