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clear;
clc;
//Example 2.30
//Given
hi=75 //[W/sq m.K)
x1=0.2 //m
x2=0.1 //[m]
x3=0.1 //[m]
T1=1943 //[K]
k1=1.25 //W/m.K
k2=0.074 ///W/m.K
k3=0.555 //W/m.K
T2=343 //K
A=1 //assume [sq m]
sigma_R=1/(hi*A)+x1/(k1*A)+x2/(k2*A)+x3/(k3*A);
//Heat loss per i sq m
Q=(T1-T2)/sigma_R //[W]
//if T=temperature between chrome brick and koalin brick then
//Q=(T1-T)/(1/(hi*A)+x1/(k1*A))
//or T=T1-(Q*(1/(hi*A)+x1/(k1*A)))
T=T1-(Q*(1/(hi*A)+x1/(k1*A))); //[K]
printf("Temperature at inner surface of middle layer=%f K(%f degree C)",T,T-273);
//if Tdash=temperature at the outer surface of middel layer,then
//Q=(Tdash-T2)/(x3/(k1*A))
//or Tdash=T2+(Q*x3/(k3*A))
Tdash=T2+(Q*x3/(k3*A)) //[K]
printf("Temperature at outer surface of middle layer=%f K (%f degree C)",Tdash,Tdash-273);
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