blob: da1f59cfa3e9920fee58d777cbcc1547352aec79 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
|
//Exaample2.21
//Given
k1=0.7 //common brick W/((m.K)
k2=0.48 //gypsum layer [W/(m.K)
k3=0.065 //Rockwool [W/m.K]
//Heat loss with insulatiob will be 20% of without insulation
A=1 //sq m
x1=0.1 //[m]
x2=0.04 //[m]
R1=x1/(k1*A) //K/W
R2=x2/(k2*A) //K/W
R=R1+R2 //K/W
//R3=x3/(k3*A)
QbyQd=0.2
sigRbyRd=QbyQd
x3=(R/QbyQd-R)/15.4 //m
x3=x3*1000 //[mm]
printf("Thickness of rockwool insulation =%f mm",x3)
|
