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//Example2.17
T1=523 //[K]
T2=323 //[K]
r1=0.05 //[m]
r2=0.055 //[m]
r3=0.105 //[m]
r4=0.155 //[m]
k1=50 //[W/(m.K)]
k2=0.06 //[W/(m.K)]
k3=0.12 //W/(m.K)
//CASE 1
Q_by_L1=2*%pi*(T1-T2)/((log(r2/r1))/k1+(log(r3/r2))/k2+(log(r4/r3))/k3) //[W/m]
printf("Heat loss=%f W/m",Q_by_L1)
//Case 2
Q_by_L2=2*%pi*(T1-T2)/((log(r2/r1))/k1+(log(r3/r2))/k3+(log(r4/r3))/k2)
perct=(Q_by_L2-Q_by_L1)*100/Q_by_L1
printf("If order is changed then heat loss=%f W/m",Q_by_L2)
printf("\n loss of heat is increased by %f percent by putting material with higher thermal conductivity near the pipe surface",perct)
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