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//chapter9,Example9_9,pg 240
lam=0.58*10^-10
theta1=6.5*(%pi/180)
theta2=9.15*(%pi/180)
theta3=13*(%pi/180)
//from bragg's law
d1=lam/(2*sin(theta1))*10^10
d2=lam/(2*sin(theta2))*10^10
d3=lam/(2*sin(theta3))*10^10
printf("interplannar spacing of crystal\n")
printf("%.2f:",d1);printf("%.2f:",d2);printf("%.2f",d3);
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