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//chapter9,Example9_8,pg 239
//from bragg's law
//2*d*sin(theta)=n*lam
n=1
theta1=5.4*(%pi/180)
theta2=7.6*(%pi/180)
theta3=9.4*(%pi/180)
lam = 2
d100=lam/2*sin(theta1)
d110=lam/2*sin(theta2)
d111=lam/2*sin(theta3)
printf("ratio of interplannar spacing \n(1/d100):(1/d110):(1/d111)=")
printf("%.2f:",sin(theta1));printf("%.2f:",sin(theta2));printf("%.2f",sin(theta3));
printf("\nas ratio (1/d100):(1/d110):(1/d111)=1:sqrt(2):sqrt(3)this relation is valid for simple cubic crystal therefore, this is a SCC crystal")
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