1026/CH6/EX6.20/Example6_20.sce


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//chapter6,Example6_20,pg 149

V=1.5

R=10^3

Ic=V/R

alpha=0.96

Ie=Ic/alpha

Ib=Ie-Ic

printf("base current\n")

printf("Ib=%.6f A",Ib)