1026/CH6/EX6.16/Example6_16.sce


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//chapter6,Example6_16,pg 148

Ie=1*10^-3

Ib=0.02*10^-3

Ic=Ie-Ib

B=Ic/Ib

alpha=Ic/Ie

printf("alpha=%.2f \n",alpha)

printf("B=%.2f \n",B)