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//Example 3.13
clear;
clc;
//Given
delHfNaOH = -470.7;//heat of formation in kJ of NaOH
delHfOH = -228.8;//heat of formation of OH- ions in kJ
//To determine the heat of formation of sodium ions
delHNa = delHfNaOH-delHfOH;//heat of formation of sodium ions in kJ
mprintf('heat of formation of sodium ions = %f kJ',delHNa);
//end
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