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+clc;
+clear all;
+disp("To find area of superheater")
+r1=35/2;//mm inner radius of pipe
+r2=45/2;//mm outer radius of pipe
+kA=38.5;// W/(m*C) thermal conductivity of pipe material
+ho=82;// W/(m^2*C)
+hi=1120;// W/(m^2*C)
+to= 920;// degree C
+Cps=192;//kJ/(kg*C)
+ms=55;//kg
+tsup=480;// degree C
+tsat=324.6;// degree C
+ti=(tsup+tsat)/2;
+Q=ms*Cps*(tsup-tsat);//kJ/s
+//Q=2*3.1416*L*(to-ti)/(1000/(ho*r2)+(log(r2/r1))/k+1000/(hi*r1));
+L=(16410.24*10^(3))/5425.8
+disp("m")
+A=2*3.1416*r2*L/1000;
+disp("m^2",A,"Outer surface area of superheater = ")
+
+
+