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+clc;
+clear all;
+disp("case 1:Without extra layer of lagging")
+r1=70/2;//mm inner radius of pipe
+r2=85/2;//mm outer radius of pipe
+r3=r2+35;//mm radius of insulation layer 1
+r4=r3+25;//mm radius of insulation layer 2
+L=50;//m
+kA=45;// W/(m*C) thermal conductivity of pipe material
+kB=0.15;// W/(m*C) thermal conductivity of layer 1
+kC=0.075;// W/(m*C) thermal conductivity of layer 2
+hhf=220;// W/(m^2*C)
+hcf=6.5;// W/(m^2*C)
+ts= 350;// degree Ctemperature of steam
+ta=30;// ambient temperature
+
+Q=2*3.1416*L*(ts-ta)/(1000/(hhf*r1)+(log(r2/r1))/kA+(log(r3/r2))/kB+(log(r4/r3))/kC+1000/(hcf*r4));
+disp("W",Q,"Loss of heat")
+
+disp("To find overall heat transfer coefficients Ui,Uo")
+//Q=Uo*Ao*delT=Ui*Ai*delT
+delT=ts-ta;
+Ao=2*3.1416*r4*10^(-3)*L;//m^2
+Ai=2*3.1416*r1*10^(-3)*L;//m^2
+Ui=Q/(Ai*delT);//W/(m^2*C)
+Uo=Q/(Ao*delT);//W/(m^2*C)
+disp("W/(m^2*C)",Uo,"overall heat transfer coefficient Uo = ")
+disp("W/(m^2*C)",Ui,"overall heat transfer coefficient Ui = ")
+
+
+