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+//example 3.17
+
+clear;
+clc;
+
+//Given:
+Cp1=poly([29.07, -0.836*10^-3, 20.1*10^-7],'T','c');//heat capacity for H2(g)
+Cp2=poly([25.72, 12.98*10^-3, -38.6*10^-7],'T','c');//heat capacity for O2(g)
+Cp3=poly([30.36, 9.61*10^-3, 11.8*10^-7],'T','c');//heat capacity for H2O(g)
+Hf1=-241820;//standard heat of formation H2O(g) at 298K : H2(g)+ 0.5O2(g)->H2O(g) [J/mol]
+T1=298;//initial temperature[K]
+T2=1273;//final temperature[K]
+
+//to find the standard heat of formation of H2O(g) at 1273K
+Cp=Cp3-0.5*Cp2-Cp1;//heat capacity for the formation[J/K/mol]
+i=horner(Cp,1273)-horner(Cp,298);//[J/mol]
+Hf2=(Hf1-i)*0.001;//[KJ/mol]
+printf("The heat of formation of H2O at 1273K = %f KJ/mol", Hf2);
+
+
+